Find the number of tiles of dimensions $1 m \times 0.8 m$ required to cover a floor of dimensions $80 m \times 120 m$ .

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Detailed Solution

Concept- We then determine the area of each tile and the total area of the floor using the formula Area of rectangle=

because the given floor and tiles are rectangular in shape and we have been given their dimensions. To get the necessary number of tiles, divide the floor's overall area by the area of one tile.
Given,
The dimensions of floor =1m×0.8m and
The dimensions of the tile = 80m×120m
Question Image

The quantity of tiles needed to cover a floor must be determined.
Let the floor measure 120 m in length and 80 m wide.
We first determine the floor's area since it has a rectangular shape.
The floor's area the rectangle's area= (length x width).

Similarly, we now determine the area of a tile with dimensions of 1 m x 0.8 m.
Assume that each tile is 1 m in length and 0.8 m wide.
The area of the floor will be equal to Area of rectangle=length × width, because the tile is rectangular in shape.

The quantity of tiles needed to cover a floor will now be
=