Find the number of ways in which 8 different flowers can be strung to form a garland so that 4 particular flowers are never separated

Considering 4 particular flowers as one flower we have five flowers which can be strung to form a garland in $\frac{4!}{2}$ ways. But 4 particular flowers can be arranged in 4! Ways

Required number of ways $=\frac{4!}{2!}\times 4!=\frac{576}{2}=288$.