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Find the number of ways of preparing a chain with 6 different coloured beads.

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detailed solution

1

We know that the number of circular permutations of hanging type that can be formed using n things is $\frac{\left(n-1\right)!}{2}$

Here the number of different ways of preparing the chain with n = 6

different coloured beads is$\frac{\left(6-1\right)!}{2}=\frac{5!}{2}=\frac{120}{2}=60$

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