Find the number of yellow coloured water insoluble compound.PbI2 PbCrO4 KI NaIAg2CrO4 BaCrO4 K2CrO4 NH43PO4⋅12MoO3HgO AgI AgCl

The number of yellow coloured water insoluble compound are PbI2,PbCrO4,BaCrO4,NH43PO4⋅12MoO3'AgI,HgOThey are 6 in number, so the correct answer is 6.

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Find the number of yellow coloured water insoluble compound.
$\begin{array}{llll} {PbI}_{2} {PbCrO}_{4} KI NaI \\ {Ag}_{2} {CrO}_{4} {BaCrO}_{4} K_{2} {CrO}_{4} {({NH}_{4})}_{3} {PO}_{4} \cdot 12 {MoO}_{3} \\ HgO AgI AgCl \end{array}$

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answer is 6.

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The number of yellow coloured water insoluble compound are

$\begin{array}{l} {PbI}_{2}, {PbCrO}_{4}, {BaCrO}_{4}, {({NH}_{4})}_{3} {PO}_{4} \cdot 12 {MoO}_{3'} \\ AgI, HgO \end{array}$

They are 6 in number, so the correct answer is 6.

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