Find the number of $p\pi -p\pi$ bonds in ${\mathrm{N}}_2\mathrm{O}$?

Nitrogen has a remarkable capacity to create $p\pi -p\pi$ numerous bonds with itself and other elements because of its tiny size and strong electronegativity. The inner core of nitrogen includes solely 1s electrons. There is no repulsion between non-bonded electrons in the inner core. As a result, p orbitals easily overlap to generate pi bonds.

${\mathrm{N}}_2$clearly has two pi bonds and one sigma bond.