Find the number or element.& which are isodiapher of ${ }_{92}{\mathrm{U}}^{238}$

${ }_{93}{\mathrm{Th}}^{234}{,}_{90}{\mathrm{Th}}^{232}{,}_{93}{\mathrm{Np}}^{237}{,}_{96}{\mathrm{Cm}}^{247}$

 Isodiapheres are a class of nuclides that differ in the number of protons and neutrons they contain but share the same difference between them. 

The neutron excess for the uranium is,54 found as

Neutron excess $=238-2\times 92=54$

The neutron excess for the thorium is,48 found as

Neutron excess $=234-2\times 93=48$

After solving for all the options it is obtained that the none of the elements are isodiapheres.