Find the perimeter of a rectangle whose length is 150 m and the diagonal is 170 m.

Given: Length, L = 150 m

Diagonal, H = 170 m

Let the breadth of the rectangle be B.

So, using Pythagoras Theorem,

H² = L² + B²

⇒ (170)² = (150)² + B²

⇒ B² = 28900 − 22500

⇒ B² = 6400

⇒ B = 80 m

We know, the perimeter of the rectangle = 2(L + B)

= 2(150 + 80)

= 2(230)

= 460 m

Hence, the perimeter of the rectangle is 460 m.