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Find the perimeter of a triangular – based pyramid with slant height 18 m and lateral surface area $360 m^{2}$ .

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50 m

40 m

30 m

60 m

answer is B.

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Detailed Solution

Given
Slant height l= 18 m
Lateral surface area LSA= 360

m^{2}

Suppose perimeter of triangular – based pyramid= P
Now, we know that,
Lateral surface area =

\frac{1}{2} (

perimeter of the base

\times slant height)

LSA = \frac{1}{2} Pl

360 = \frac{1}{2} \times P \times 18

360 = 9 P

P = \frac{360}{9}

P = 40 m

So, the required perimeter is 40 m.
Correct option is 2.

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