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Q.

Find the point on x-axis which is equidistant from the points P (2, -2) and Q (-4, 2).


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a

(0, -1)

b

(-1, 0)

c

(-1, 2)

d

(1, 1) 

answer is B.

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Detailed Solution

Given points are P (2, -2) and Q (-4, 2).
We need to find a point on x - axis, which lies at equal distance from the given points P and Q.
As it lies on the x – axis, the y-coordinate is 0.
So, let us consider the point is R (x, 0).
We know that,
Distance between two points = x 2 βˆ’ x 1 2 + y 2 βˆ’ y 1 2  .
Since R is at equal distance from P and Q, we get,Question Image 8βˆ’4x=20+8x 8βˆ’20=8x+4x   βˆ’12=12x 12x=βˆ’12 x= βˆ’12 12 x=βˆ’1  
The required point on x-axis which is equidistant from given points P (2, -2) and Q (-4, 2) is (-1,0).
The correct option is (2).
 
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