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Find the points where the graph of the given equation $3 x + 4 y = 12$ cuts the x-axis and the y-axis respectively.

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(0, 3)

and

(4, 0)

(3, 0)

and

(0, 4)

(4, 0)

and

(0, 3)

(0, 4)

and

(3, 0)

answer is C.

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Detailed Solution

The given equation is

3 x + 4 y = 12

⇒ 4 y = 12 − 3 x ⇒ y = 12 − 3 x 4

To find out the point which cut x-axis, substitute

y = 0

in the above equation:

⇒ 4 y = 12 − 3 x ⇒ 0 = 12 − 3 x 4 ⇒ 0 = 12 − 3 x ⇒ 3 x = 12 ⇒ x = 4

The point obtained is

(4, 0)

.
To find out the point which cut y-axis, substitute

x = 0

in the above equation:

⇒ y = 12 − 3 (0) 4 ⇒ y = 3

The point obtained is

(0, 3)

Therefore, the graph cuts the x-axis at

(4, 0)

and y-axis at

(0, 3)

.
Hence, option 3 is the correct answer.

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