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Find the potential difference between A and C point in the term of $ε .$ If battery has emf $2 ε .$

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$ε$

$2 ε$

$3 ε$

$4 ε$

answer is A.

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Detailed Solution

$i$ from Battery $= \frac{2 ε \times 3}{2 R} = \frac{3 ε}{R}$
$V_{A} = 2 ε V_{C} = ε$
$V_{A} = V_{C} = ε$

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