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Q.

Find the potential energy of three objects of masses 1 kg, 2kg, 3kg placed at three vertices of an equilateral triangle of '10 cm'

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a

-110 GJ

b

-240 GJ

c

-60 GJ

d

-5 GJ

answer is B.

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Detailed Solution

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$U = - \frac{{Gm}_{1} m_{2}}{r}$

$U = - \frac{G}{r} [(1 X 2) + (2 X 3) + (3 X 1)]$

$U = - \frac{G}{10 X 10^{- 2}} [2 + 6 + 3]$

$U = - \frac{11 G}{10^{- 1}} = - 110 GJ$

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