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Find the power of an engine which can draw a train of 400 metric ton up the inclined plane of 1 in 98 at the rate of 10ms^–1. The resistance due to friction acting on the train is 10N per ton.

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350kW

400kW

440 kW

500kW

answer is C.

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Detailed Solution

$P = (F_{R} v) + (mg sinθ) v$
$P = 40000 + 400 \times 10^{3} \times 9.8 \times \frac{1}{98} \times 10 = 440 kW$

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