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Find the pressure to be applied to increase the density of water by 1% if the bulk modulus of water is $2.2 \times 10^{9} N m^{- 2}$ .

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$2.2 \times 10^{7} N / m^{2}$

$1.2 \times 10^{7} N / m^{2}$

$3.2 \times 10^{7} N / m^{2}$

$4.2 \times 10^{7} N / m^{2}$

answer is A.

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Detailed Solution

$k = \frac{- Δ p}{\frac{Δ V}{V}} \Rightarrow k = \frac{Δ p}{\frac{Δ d}{d}} \Rightarrow Δ p = k \frac{Δ d}{d} = 2.2 \times 10^{9} \times \frac{1}{100} = 2.2 \times 10^{7} P a$

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