Find the probabilities of the events given in Question 2.

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Detailed Solution

According to question 2,

(i) Total number of outcomes when a dice is thrown = 6

(a) Outcomes of the event of getting a prime number are 2, 3 and 5.

Probability of getting a prime number = $\frac{3}{6} = \frac{1}{2}$

(b) Outcomes of the event of not getting a prime number are 1, 4 and 6.

Probability of not getting a prime number = $\frac{3}{6} = \frac{1}{2}$

(ii) (a) Outcomes of the event of getting a number greater than 5 is 6.

Probability of getting a number greater than 5 = $\frac{1}{6}$

(b) Outcomes of the event of not getting a number greater than 5 are 1, 2, 3, 4 and 5.

Probability of not getting a number greater than 5 = $\frac{5}{6}$

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