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Q.

Find the probability that a non-leap year selected randomly will have 53 sundays?

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a

17

b

37

c

47

d

27

answer is D.

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Detailed Solution

detailed_solution_thumbnail

Let S = {Mon, Tue, Wed, Thu, Fri, Sat, Sun} 

and A= {Sun} 

Hence, the required probability =P(A)=n(A)n(S)=17

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