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Q.

Find the probability that a non-leap year selected at random will contain 53 sundays.


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a

1 6  

b

1 20  

c

1 7  

d

1 4   

answer is C.

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Detailed Solution

Given, a non-leap year.
Probability is the favourable outcome from a no of events.
In a non-leap year, there are 365​ days.
There are 365 days in a non-leap year.
A year has 52 weeks.
So, 52 sundays are present in a year. So total no of days =52×7=364   .
So number of extra days =365364=1   day.
So, this day can be sunday, monday, tuesday, wednesday, thursday, friday, saturday.
So total number of events = total no of days =7   .
The probability that a non-leap year selected at random will contain 53 sundays is 1 7   .
Hence, the correct option is 3.
 
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Find the probability that a non-leap year selected at random will contain 53 sundays.