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Find the quadratic equation whose zeroes are –3 and 4?

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x^{2} - x + 12 = 0

x^{2} + x + 12 = 0

\frac{x^{2}}{2} - \frac{x}{2} - 6 = 0

2 x^{2} + 2 x - 24 = 0

answer is C.

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Detailed Solution

Let

α = - 3

and

β = 4

x^{2} - (α + β) x + αβ = 0

{\Rightarrow x}^{2} - (- 3 + 4) x + (- 3) 4 = 0

{\Rightarrow x}^{2} - x - 12 = 0

\Rightarrow \frac{x^{2}}{2} - \frac{x}{2} - 6 = 0

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