Find the radius of the base of a cylindrical container of volume 440 cm³, and a height of 35 cm.

Given that, the volume of the cylinder is 440 cm³ and the height is 35 cm.

$\begin{array}{c}\mathrm{Now}, \mathrm{V}={\mathrm{\pi r}}^2\mathrm{h}= 440\\ \Rightarrow {\mathrm{r}}^2= \frac{440\times 7}{22\times 35}=\frac{3080}{770}= 4 \\ \Rightarrow \mathrm{r}= 2 \mathrm{cm}.\end{array}$

Therefore the radius of the cylinder = 2 cm.