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Q.

Find the radius of the soap bubble if 44 $\times$ 10^-6 J of work is done in blowing the soap bubble. Surface tension of soap solution = 7 $\times$ 10^-2Nm^-1

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a

2mm

b

4 mm

c

5 mm

d

8 mm

answer is C.

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Detailed Solution

$\begin{array}{l} W = 8 {πr}^{2} \cdot S ∴ r^{2} = \frac{W}{8 πS} \\ r = \sqrt{\frac{W}{8 πS}} = \sqrt{\frac{44 \times 10^{- 6}}{8 \times \frac{22}{7} \times 7 \times 10^{- 2}}} = \sqrt{\frac{1}{4} \times 10^{- 4}} \\ ; r = 0 .005 m (or) 5 mm \end{array}$

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