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Q.

Find the range of f(x) = sin2x - 3 sin x + 2.
Mathematics
Area of Circle

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a

0,6

b

6,0

c

1,6

d

1,2

answer is A.

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Detailed Solution

f(x) = sin2x - 3 sin x + 2
= (sinx - 3/2)2 +2- 9/4
= (sin x- 3/2)2 -1/4
Now, -1 ≤ sin x ≤ 1
= -5/2 ≤ sinx ≤ 1
= ¼ ≤ (sinx -3/2)2 ≤ 25/4
=0 ≤ (sinx -3/2)2 -1/4 ≤ 6
= 0 3/2)2 ≤ F(x) 3/2)2 ≤ 6
Hence, we get the range f(x) = (0,6).
Type : CBSE
Class: Grade 10

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