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Q.

Find the range of f(x) = sin2x - 3 sin x + 2.

Mathematics 

Area of Circle 

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a

0,6 

b

6,0 

c

1,6

d

1,2 

answer is A.

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Detailed Solution

 f(x) = sin2x - 3 sin x + 2
= (sinx - 3/2)2 +2- 9/4
= (sin x- 3/2)2 -1/4
Now, -1 ≤ sin x  ≤ 1
= -5/2  ≤ sinx  ≤ 1
= ¼  ≤ (sinx -3/2)2  ≤ 25/4
=0  ≤ (sinx -3/2)2  -1/4 ≤ 6
= 0 3/2)2  ≤ F(x) 3/2)2  ≤ 6 
Hence, we get the range f(x) = (0,6).
    Type :  CBSE
Class:   Grade 10
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