Find the reading of the ideal ammeter connected in the given circuit. Assume that the cells have negligible internal resistance.

$$\begin{gathered} \begin{array}{l}\mathrm{In}\mathrm{loop}\mathrm{efhge},-4{\mathrm{I}}_2+2{\mathrm{I}}_1+8=0\Rightarrow \\ \mathrm{In}\mathrm{loop}\mathrm{cdfec},-8{\mathrm{I}}_3+4{\mathrm{I}}_2-4=0\Rightarrow \\ \mathrm{In}\mathrm{loop}\mathrm{abdca},-10{\mathrm{I}}_4+8{\mathrm{I}}_3+10=0\end{array} \\ in loop abjia -10I_4-6+8-4+10=0 \\ {I}_4=\frac{8}{10}=\frac{4}{5}A, I_3=-\frac{1}{4}A, I_2=\frac{1}{2}A, I_1=-3A \end{gathered}$$

Current through ammeter $={\mathrm{I}}_1+{\mathrm{I}}_2+{\mathrm{I}}_3+{\mathrm{I}}_4$

$=\frac{-60+10-5+16}{20}=\frac{39}{20}\mathrm{A}=1.95\mathrm{A}$