Find the remainder when x3+3x2+3x+1 is divided by x+π.

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

−π2+3π3−3π+1

−π3+3π2−3π+1

None of these

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Let us first of all mention what the remainder theorem says:-
Remainder theorem: The Remainder Theorem states that if a polynomial f (x) is divided by (x - k) then the remainder r = f (k), where r is the remainder.
If we compare this to the given situation to us with this remainder theorem:-
We have f(x) = x3+3x2+3x+1 and k = −π.
So, the required remainder should be f(−π).
Since, f(x)= x3+3x2+3x+1
Therefore, f(−π)=(−π)3+3(−π)2+3(−π)+1
We know that the cube of negative is also negative but the square of negative is always positive.
⇒f(−π)=−π3+3π2−3π+1
Hence, the required correct answer is (3).

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th