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Q.

Find the resistance of a cube of edge 60cm, made of a material of specific resistance $60 \times 10^{- 8} Ω m$

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a

$10^{- 6} Ω$

b

$5 \times 10^{- 5} Ω$

c

$2.5 \times 10^{- 5} Ω$

d

$10^{- 8} Ω$

answer is C.

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Detailed Solution

$l = 60 \times 10^{- 2} m, P = 60 \times 10^{- 8} Ω m$

$R = \frac{P l}{A} = 60 \times 10^{- 8} \frac{\times 60 \times 10^{- 2}}{(60 \times 10^{- 2})}$

$R = 10^{- 6} Ω$

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