Find the slant height of frustum cone, if the frustum is of height $22 cm$ and has its diameter as $34 cm$ and $50 cm$?

Given,

Height of frustum ($h$) = $22 cm$

Diameter ($d_1$) of frustum = $34 cm$

Radius ($r_1$) of frustum = $\frac{34}{2}=17cm$

Diameter ($d_2$) of frustum = 50 cm

Radius ($r_2$) of frustum = $\frac{50}{2}=25cm$
The slant height of a cone (s²) = h² + (R – r)²
s² = 484 + (25 – 17)²
s² = 548
s = $23.40 cm$