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Q.

Find the smallest number which when increased by 17 is exactly divisible by both 520 and 468.

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a

5437

b

4663

c

6545

d

6789 

answer is B.

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Detailed Solution

The smallest numbers are 520 and 468
The smallest numbers that are exactly divisible by both 520 and 468 when multiplied by 17 are obtained by subtracting 17 from the LCM of 520 and 468.
Question ImageLCM of 520 and 468
Question ImageSmallest number which when increased by 17 is exactly divisible by both 520 and 468
Question ImageHence, option 2 is correct.
 
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Find the smallest number which when increased by 17 is exactly divisible by both 520 and 468.