Find the smallest square no. which is divisible by each of the numbers 8, 15 and 20

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3500

3600

3800

3200

answer is B.

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Detailed Solution

We have to find LCM of 8, 15 and 20
8=2×2×2
15=3×5
20=2×2×5
So, LCM =2×2×2×3×5=120.
For which are not in pairs in LCM factors, we need to multiply 120 by 2, 3 and 5 to make it a perfect square.
Required Number =120×2×3×5 = 3600

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