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Find the smallest value of the sum of x and y, so that the number 5x7y1 is divisible by 3?

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answer is D.

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Detailed Solution

Here, Sum of the known digits of 5x7y1 = 5 + x+7 +y +1 = 13+x+y

Now, the number next to 13, which is divisible by 3 is 15.

Thus, if we replace the x+y by 2, the sum of digits will become 15 and the number becomes divisible by 3.

Hence, x+y is replaced by 2.

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