Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Find the square root of: ____.
6 + 12-24-√8


see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Concepts: The square root would be 1.7375.
Try to take out common terms in order to make calculation easier.
Given: 6 + 12-24-√8
Rewriting above equation as:
⇒36 + 12-24-√8{∵–36 + 12-24-8

Taking 12 common from first two terms and √4 from other two terms, we get
123-2+√4(3-2)

Now, taking out (3-√2) common from above equation, we know the value of √3 is 1.7321.732 and of √2 is 1.4141.414
Hence, putting these values in (1), we get
∴2×(1.732+1)(1.732−1.414) ⇒ 2×2.732×0.318 ⇒ 1.73

Hence, the answer is 1.7375
 
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring