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Q.

Find the sum of first n odd natural numbers.


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a

n3

b

n(n+1)

c

n(n+1)2

d

n2  

answer is D.

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Detailed Solution

We have to find the sum of first n odd natural numbers.
The sum of first n odd numbers is 1+3+5+...to n terms.
The first term a=1
Common difference d=3-1=2
Sum of n terms is Sn=n2[2a+(n-1)d]
⇒Sn=n2[2×1+(n-1)×2] ⇒Sn=n2[2+2n-2] ⇒Sn=n2 Therefore, option 4 is correct.
 
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