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Q.

Find the sum of molarity of all the ions present in an aqueous solution of $5 M {NaNO}_{3}$ and 3 m ${BeCl}_{2}$ ? The specific gravity of the given solution is 1.665. Assume 100% dissociation of each salt. $[Be = 9]$

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Detailed Solution

Let 1 L of solution is taken

$3 = \frac{n \times 1000}{1665 - 5 \times 85 - 80 \times n}$

$\Rightarrow n = 3$

$[{Na}^{+}] = 5, [{NO}_{3}^{-}] = 5, [{Be}^{2 +}] = 3, [{Cl}^{-}] = 6$

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Find the sum of molarity of all the ions present in an aqueous solution of 5M NaNO3 and 3 m BeCl2? The specific gravity of the given solution is 1.665. Assume 100% dissociation of each salt. [Be=9]