Find the total number of diamagnetic complexes. 

$\begin{array}{l}{\mathrm{K}}_3\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right],\left[\mathrm{Co}{\left({\mathrm{NH}}_3\right)}_6\right]{\mathrm{Cl}}_3,{\mathrm{Na}}_3\left[\mathrm{Co}(\mathrm{Ox}{)}_3\right]\\ \left[\mathrm{Ni}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]{\mathrm{Cl}}_2,{\mathrm{K}}_2\left[\mathrm{Pt}\left({\mathrm{CN}}_4\right],\left[\mathrm{Zn}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]{\left({\mathrm{NO}}_3\right)}_2\right.\\ {\mathrm{K}}_2\left[{\mathrm{NiCl}}_4\right],\left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_2{\mathrm{Cl}}_2\right],\left[\mathrm{Ni}(\mathrm{CO}{)}_4\right]\end{array}$

When ions do not have any unpaired electron, then they are known as diamagnetic complexes ions. The diamagnetic complexes are,

$\begin{array}{l}\left[\mathrm{Co}{\left({\mathrm{NH}}_3\right)}_4\right]{\mathrm{Cl}}_8,{\mathrm{Na}}_3\left[\mathrm{Co}(\mathrm{Ox}{)}_3\right\}{\mathrm{K}}_2\left[\mathrm{Pt}\left({\mathrm{CN}}_4\right]\right.\\ \left[\mathrm{Zn}\left({\mathrm{H}}_2{\mathrm{O}}_6\right]{\left({\mathrm{NO}}_3\right)}_2\right.\\ \left[\mathrm{Pt}{\left({\mathrm{NH}}_3\right)}_2{\mathrm{Cl}}_2\right],\left[{\mathrm{Ni}}_2\left({\mathrm{CO}}_4\right]\right.\end{array}$

Hence correct answer is 0006