Find the total number of protons in 34 mg of NH3 at STP. (Mass of 1p=1.6726×10−27kg ).

1 mole of NH3, contains protons = 7+3 = 10 moles of protons (7 in N and 1 in each H atom)=6.023×1023×10 protons 34×10−3g NH3 will contain =34×10−3×6.023×102417=12.046×1021 protons

Find the total number of protons in 34 mg of NH3 at STP. (Mass of 1p=1.6726×10−27kg ).

1 mole of NH3, contains protons = 7+3 = 10 moles of protons (7 in N and 1 in each H atom)=6.023×1023×10 protons 34×10−3g NH3 will contain =34×10−3×6.023×102417=12.046×1021 protons

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Find the total number of protons in 34 mg of NH₃ at STP. $(Mass of 1 p = 1 .6726 \times 10^{- 27} kg).$

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$12, 044 \times 10^{20}$

$12.044 \times 10^{21}$

$12.044 \times 10^{23}$

$12.044 \times 10^{22}$

answer is C.

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Detailed Solution

1 mole of NH₃, contains protons = 7+3 = 10 moles of
protons (7 in N and 1 in each H atom)
$= 6.023 \times 10^{23} \times 10 protons$

$\begin{array}{l} 34 \times 10^{- 3} g {NH}_{3} will contain \\ = \frac{34 \times 10^{- 3} \times 6 .023 \times 10^{24}}{17} = 12 .046 \times 10^{21} protons \end{array}$