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Find the total surface area of a frustum, whose slant height is 18 cm and has radii of 8 cm and 16 cm.

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900π cm²

850π cm²

752π cm²

742π cm²

answer is A.

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Detailed Solution

Given: Slant height of the frustum (l) = 18 cm

Radius of the upper base of the frustum (r₁) = 16 cm

Radius of the lower base of the frustum (r₂) = 8 cm

Therefore, the total surface area of the frustum

= π(r₁ + r₂)l + π(r₁² + r₂²)

= π(16 + 8)×18 + π(16² + 8²)

= 432π + 320π

= 752π cm²

Therefore, the total surface area of the frustum is 752π cm².

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