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Find the total surface areas of the following cylinders.

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1936 {cm}^{2}

and

50.28 m^{2}

1932 {cm}^{2}

and

57.28 m^{2}

1930 {cm}^{2}

and

55.28 m^{2}

1928 {cm}^{2}

and

49.28 m^{2}

answer is A.

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Detailed Solution

Total surface area of cylinder can be given as,

TSA = 2 π r^{2} + 2 πrh = 2 πr (r + h)

Here, r = radius
h =height of cylinder
Now the figure of first cylinder is,
Question Image

Here, radius r=14 cm
Height h=8 cm
Therefore, its overall surface area

= 2 πr (r + h)

= 2 \times \frac{22}{7} \times 14 \times (14 + 8)

= 1936 {cm}^{2}

Now, the figure of second cylinder is,
Question Image

Here, radius r=2 m
Height h=2 m
Therefore, its overall surface area

= 2 πr (r + h)

= 2 \times \frac{22}{7} \times 2 \times (2 + 2)

= 50.28 m^{2}

So, total surface areas of first cylinders is

1936 {cm}^{2}

and second cylinder is

50.28 m^{2}

.
So, option 1 is correct.

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