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Find the units of electrical energy consumed in the month of July when an electric iron of $1600 W$ is used for $45 minutes$ every day.

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41.7

units

37.2

units

24.6

units

12.8

units

answer is B.

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Detailed Solution

The total units consumed in the month of July is

37.2

units.
Given, the power rating of the electric iron,

P = 1600 W

\Rightarrow P = 1.6 kW

Total time of usage

= 31 \times \frac{45}{60}

hours (number of days in July is

31

)
Number of units of electrical energy consumed

= 1600 \times 31 \times \frac{45}{60} kWh

\Rightarrow E = 37.2 kWh

\Rightarrow E = 37.2 units

(

1 kWh = 1

unit of electric energy)
Therefore, total units consumed in the month of July is

37.2 units

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Find the units of electrical energy consumed in the month of July when an electric iron of 1600 W is used for 45 minutes every day.

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Find the units of electrical energy consumed in the month of July when an electric iron of $1600 W$ is used for $45 minutes$ every day.