Q.

Find the value of π‘˜, if βˆ’ 1 is one of the zeros of the polynomial

𝑝(π‘₯) = π‘˜π‘₯2 βˆ’ 4π‘₯ + π‘˜.

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Detailed Solution

We are given that βˆ’ 1 is a zero of the polynomial 𝑝(π‘₯) = π‘˜π‘₯2 βˆ’ 4π‘₯ + π‘˜, and we have to find the value of π‘˜.

As βˆ’ 1 is a zero of the polynomial, on putting βˆ’ 1 in place of π‘₯, the value of the polynomial will become zero, i.e.,

𝑝(βˆ’ 1) = 0

β‡’ π‘˜(βˆ’ 1)2 βˆ’ 4 Γ— (βˆ’ 1) + π‘˜ = 0

β‡’ π‘˜ Γ— 1 + 4 + π‘˜ = 0

β‡’ π‘˜ + π‘˜ + 4 = 0

β‡’ 2π‘˜ + 4 = 0

β‡’ 2π‘˜ =βˆ’ 4

β‡’ π‘˜ = -4/2

β‡’ π‘˜ =βˆ’ 2

Hence, the value of π‘˜ is βˆ’ 2.

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