Q.

Find the value of: 1 sin 10 -3 cos 10 


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a

4

b

3

c

2

d

1 

answer is A.

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Detailed Solution

Given expression is,
1 sin 10 -3 cos 10 
Suppose, S=1sin10-3cos10
When 2 is multiplied and divided we get,
S=212sin10-32cos10
S=2sin30sin10-cos30cos10                       sincesin30=12,cos30=32
 S=2sin30cos10-cos30sin10sin10cos10
S=2sin20sin10cos10                 since,sinAcosB-cosAsinB=sinA-B
S=2×2sin10cos10sin10cos10             sin2θ=2sinθcosθ
S=4
Thus, 1 sin 10 -3 cos 10 =4
Hence, option 1 is correct.
 
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