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Q.

Find the value of 'b' x2 +bx+ 1 > 0.

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a

-6 < b < 3

b

-2 < b < 2

c

-4 < b < 2

d

-4 < b < 4

answer is D.

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Detailed Solution

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The given in equation is

x2+bx+1>0

It is true only when b2 - 4 < 0

(b + 2) (b - 2) < 0 -2 < b < 2

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