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Q.

Find the value of cot 70° + 4 cos 70°

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a

\sqrt{2}

b

\sqrt{3}

c

0

d

5

answer is B.

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Detailed Solution

we have a = cot 70° + 4 cos 70°
⇒ a =cot (90o – 20o) + 4 cos (90o – 20o)
⇒ a =tan 20o + 4 sin 20o

Using cos C + cos D = 2

\cos \frac{(C + D)}{2} \sin \frac{(C - D)}{2}

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