Find the value of k, if the straight lines 6x – 10y + 3 = 0 and kx – 5y + 8 = 0 are parallel.

$\text{ If }{\mathrm{a}}_1\mathrm{x}+{\mathrm{b}}_1\mathrm{y}+{\mathrm{c}}_1=0\text{ and }{\mathrm{a}}_2\mathrm{x}+{\mathrm{b}}_2\mathrm{y}+{\mathrm{c}}_2=0\text{ are }$$\text{ parallel, then }\frac{{\mathrm{a}}_1}{{\mathrm{a}}_2}=\frac{{\mathrm{b}}_1}{{\mathrm{b}}_2}\ne \frac{{\mathrm{c}}_1}{{\mathrm{c}}_2}$
Given lines
$\begin{array}{l}6\mathrm{x}-10\mathrm{y}+3=0 ...\left(1\right)\\ \mathrm{kx}-5\mathrm{y}+8=0 ... \left(2\right)\end{array}$
(1) and (2) are parallel then
$\frac{6}{\mathrm{k}}=\frac{-10}{-5}\ne \frac{3}{8}\Rightarrow \frac{6}{\mathrm{k}}=2\Rightarrow \mathrm{k}=3$