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Q.

Find the value of magnetic field between plates of capacitor at a distance 1 m from centre, where electric field varies by 10¹⁰ V/m per second.

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a

$5.56 \times 10^{- 8} T$

b

$5.56 \times 10^{- 3} T$

c

$5.56 μ T$

d

5.56 T

answer is A.

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Detailed Solution

$B = \frac{μ_{0} ε_{0} r}{2} \frac{dE}{dt} = \frac{1}{9 \times 10^{16} \times 2} \times 10^{10}$

$= 5.56 \times 10^{- 8} T$

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