Find the value of x and y: 

2x + 3y = 0, 3x + 4y = 5 

Given system of equations are: 

2x + 3y = 0  —(i) 

3x + 4y = 5  —(ii) 

Multiply (i) by 4 and (ii) by 3, we get: 

 8x + 12y = 0  —(iii) 

 9x + 12y = 15 —(iv) 

Subtract (iii) from (iv) we get: 

x = 15 

Substitute the value of x = 15 in (i), we get: 

30 + 3y = 0 

$\Rightarrow$3y = -30 

$\Rightarrow$y = -10 

Hence, the solution is x = 15 and y = -10.