Find the value of 1+sin⁡2A+1−sin⁡2A1+sin⁡2A−1−sin⁡2A; When |tan⁡A|<1 and |A| is acute.

cosA+sinA2+cosA-sinA2cosA+sinA2-cosA-sinA2=cos⁡A+sin⁡A+cos⁡A−sin⁡Acos⁡A+sin⁡A−cos⁡A+sin⁡A=cotA

Find the value of 1+sin⁡2A+1−sin⁡2A1+sin⁡2A−1−sin⁡2A; When |tan⁡A|<1 and |A| is acute.

cosA+sinA2+cosA-sinA2cosA+sinA2-cosA-sinA2=cos⁡A+sin⁡A+cos⁡A−sin⁡Acos⁡A+sin⁡A−cos⁡A+sin⁡A=cotA

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Find the value of $\frac{\sqrt{1 + \sin 2 A} + \sqrt{1 - \sin 2 A}}{\sqrt{1 + \sin 2 A} - \sqrt{1 - \sin 2 A}}$ ; When $| \tan A | < 1 and | A |$ is acute.

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cot A

cos A

sec A

sin A

answer is A.

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$\frac{\sqrt{{(\cos A + \sin A)}^{2}} + \sqrt{{(\cos A - \sin A)}^{2}}}{\sqrt{{(\cos A + \sin A)}^{2}} - \sqrt{{(\cos A - \sin A)}^{2}}} = \frac{\cos A + \sin A + \cos A - \sin A}{\cos A + \sin A - \cos A + \sin A} = c o t A$

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Find the value of 1+sin⁡2A+1−sin⁡2A1+sin⁡2A−1−sin⁡2A; When |tan⁡A|<1 and |A| is acute.

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Find the value of $\frac{\sqrt{1 + \sin 2 A} + \sqrt{1 - \sin 2 A}}{\sqrt{1 + \sin 2 A} - \sqrt{1 - \sin 2 A}}$ ; When $| \tan A | < 1 and | A |$ is acute.