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Find the velocity v if liquid is incompressible and flowing in streamline as shown in the following figure [A, 2A, and 1.2A are respective are of cross-section of given tubes]

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5 m/s

$\frac{5}{3} m / s$

4 m/s

$\frac{3}{2} m / s$

answer is D.

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Detailed Solution

AV = A₁V₁ + A₂V₂
8A = 2A × 3 + 1.2A × V
2A = 1.2A × V
V = $\frac{5}{3} m / s$

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