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Find the velocity ‘v’ if liquid is incompressible and flowing in streamline as shown in the following figure (A, 2A and 1.2 A are respective area of cross - section of given tubes)

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$4 m / s$

$5 m / s$

$\frac{3}{2} m / s$

$\frac{5}{3} m / s$

answer is D.

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Detailed Solution

$A_{1} V_{1} = A_{2} V_{2} + A_{3} V_{3}$

$A \times 8 = 2 A \times 3 + 1.2 A V_{3}$

$2 = 1.2 V_{3}$

$V_{3} = \frac{5}{3} m / s$

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