Find the volume occupied by the water molecules at standard temperature and pressure. Mass of the water is 4.5 kg. Assume that, no intermolecular force is acting between the water molecules.

From the given information

Mass of water = 4.5 kg = 4500 g

Molar mass of water molecule = 18 g

Number of mole of water

$=\frac{\mathrm{m}}{\mathrm{M}}=\frac{4500}{18}=250\text{ moles }$

m = mass of substance

M = molar mass

We know from the unitary method that

22.4 litre = 1 mole

$\therefore$ 250 moles = 22.4 x 250 litre

= 5600 litre

or,

$5.6{\mathrm{m}}^3\left(1{\mathrm{m}}^3=1000\text{ litre }\right)$