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Q.

Find the work done in increasing the volume of a soap bubble by $700 %$ if its radius is $R$ and surface tension is $T$

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a

$24 π R^{2} T$

b

$6 π R^{2} T$

c

$12 π R^{2} T$

d

$π R^{2} T$

answer is A.

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Detailed Solution

$W . D = 2 \times 4 π T ({r^{2}}_{2} - {r^{2}}_{1})$

If initial volume $= v$

then final volume $= 8 v$ then radius will become $2 R$

so $W . D = 2 \times 4 π T ({(2 R)}^{2} - R^{2}) = 24 π R^{2} T$

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