Find the wrong statement for a convex lens for a real object

For a convex lens to produce a virtual image object has to be placed within the focus. If image is of same size v=u then $\begin{array}{rcl} & & \mathrm{according} \mathrm{to} \mathrm{lens} \mathrm{equation}\\ \frac{1}{\mathrm{v}}-\frac{1}{\mathrm{u}}& =& \frac{1}{\mathrm{f}}\\ & & \mathrm{for} \mathrm{real} \mathrm{object} \mathrm{and} \mathrm{virtual} \mathrm{image} \mathrm{of} \mathrm{same} \mathrm{size}\\ -\frac{1}{\mathrm{v}}-\left(-\frac{1}{\mathrm{u}}\right) & =& \frac{1}{\mathrm{f}} =0 \\ & & \mathrm{so} \mathrm{it} \mathrm{always} \mathrm{produce} \mathrm{magnified} \mathrm{virtual} \mathrm{image}.\\ & & \end{array}$