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Q.


Find the zeroes of the polynomial x 2 + 1 6 x2  .


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a

4 3 , 3 2  

b

4 3 , 3 2  

c

3 4 , 2 3  

d

3 4 , 2 3  
  

answer is A.

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Detailed Solution


Given polynomial is x 2 + 1 6 x2  . We need to find the zeroes of the given polynomial.
Zeroes of the polynomials are those where p(x)=0  .
In splitting the middle term method we split the middle term of quadratic equation in a   and b   such that,
a+b=   middle term
a×b=  product of first and third term
Let us assume that p(x)= x 2 + 1 6 x2.  
p(x)= 6 x 2 +x12 6  
Equating p(x)   to 0  we have,
6 x 2 +x12=0...(i)  
Using, splitting the middle term approach, in equation (i)  , we have,
a=9x&b=8x  
Therefore, we have,
6 x 2 +x12=0 6 x 2 +9x8x12=0 3x(2x+3)4(2x+3)=0 3x4 2x+3 =0 x= 4 3 , 3 2  
The zeroes of polynomial x 2 + 1 6 x2   are 4 3   and 3 2  .
Therefore, option 1 is correct.
 
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Find the zeroes of the polynomial x 2 + 1 6 x−2  .